AnsweredAssumed Answered

xDx Designer Automation: select component pin

Question asked by piotrek on Jan 4, 2018
Latest reply on Jan 5, 2018 by piotrek

Hello,

 

I need to select component pin, I tried Application.SelectPath and Application.SelectPathCompPin.

For example: Application.SelectPathCompPin "Schematic1", "$2I22", "", "$1P9", True does not work for me, it selects whole component $2I22, not only one pin,

Does anyone have an example how to use Application.SelectPathCompPin to select pin from component?

 

Thanks in advance for your help

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